Class 9 Test Paper Chapter - Coordinate Geometry and Atoms | GSEB Board | Detailed Solutions & Marking Scheme

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 VEDANT IGNITE TEST SERIES

Class: 9
Subject: Mathematics & Science
Board: GSEB
Chapters:
Coordinate Geometry (Point Plotting, Reflection Across X & Y Axis, Quadrants, Sign-Based Questions)
&
Atomic Structure (Isotopes, Isobars, Average Atomic Mass, Proton-Electron-Neutron Calculations)
Total Marks: 30

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SECTION A (7 MARKS)

Q.1 MCQs (1 Mark Each)

  1. The reflection of point (-4, 7) in the x-axis is:
    (a) (4, 7)
    (b) (-4, -7)
    (c) (4, -7)

Answer: (b) (-4, -7)
Marks: 1

  1. Point (6, -3) lies in:
    (a) I Quadrant
    (b) II Quadrant
    (c) IV Quadrant

Answer: (c) IV Quadrant
Marks: 1

  1. The number of neutrons in 20Ne is:
    (a) 10
    (b) 20
    (c) 30

Atomic Number of Ne = 10

Neutrons = Mass Number − Atomic Number
= 20 − 10
= 10

Answer: (a) 10
Marks: 1

==================================================

Q.2 Fill in the Blanks (1 Mark Each)

  1. The average atomic mass of an element having 50% isotope of mass 10 u and 50% isotope of mass 12 u is ______.

Average Atomic Mass
= (50 × 10 + 50 × 12)/100
= (500 + 600)/100
= 1100/100
= 11 u

Answer: 11 u
Marks: 1

  1. The reflection of point (8, -5) in the y-axis is ______.

(8, -5) → (-8, -5)

Answer: (-8, -5)
Marks: 1

==================================================

Q.3 True or False (1 Mark Each)

  1. The point (-5, 4) lies in the second quadrant.

Answer: True
Marks: 1

  1. Isotopes have the same atomic number but different mass numbers.

Answer: True
Marks: 1

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SECTION B (2 MARKS EACH)
(Write Any 3) = 6 Marks

  1. Write the quadrant of each point:

(a) (-4, 5)

x is negative and y is positive.

Answer: II Quadrant

(b) (7, -2)

x is positive and y is negative.

Answer: IV Quadrant

Marking Scheme:
(a) 1 Mark
(b) 1 Mark
Total = 2 Marks

  1. Find the coordinates of the reflection of point (-6, -4) in:

(a) x-axis

(-6, -4) → (-6, 4)

(b) y-axis

(-6, -4) → (6, -4)

Marking Scheme:
(a) 1 Mark
(b) 1 Mark
Total = 2 Marks

  1. Calculate the number of protons, electrons and neutrons in 19F.

Atomic Number of F = 9

Protons = 9
Electrons = 9
Neutrons = 19 − 9 = 10

Answer:
Protons = 9
Electrons = 9
Neutrons = 10

Marking Scheme:
Protons = 0.5 Mark
Electrons = 0.5 Mark
Neutrons = 1 Mark
Total = 2 Marks

  1. Calculate the number of protons, electrons and neutrons in 24Mg.

Atomic Number of Mg = 12

Protons = 12
Electrons = 12
Neutrons = 24 − 12 = 12

Answer:
Protons = 12
Electrons = 12
Neutrons = 12

Marking Scheme:
Protons = 0.5 Mark
Electrons = 0.5 Mark
Neutrons = 1 Mark
Total = 2 Marks

  1. Calculate the average atomic mass of an element containing:
    40% isotope of mass 20 u and
    60% isotope of mass 22 u.

Average Atomic Mass
= (40 × 20 + 60 × 22)/100
= (800 + 1320)/100
= 2120/100
= 21.2 u

Answer: 21.2 u

Marking Scheme:
Formula = 1 Mark
Calculation & Answer = 1 Mark
Total = 2 Marks

==================================================
SECTION C (3 MARKS EACH)
(Write Any 3) = 9 Marks

  1. Plot the points A(3, 2), B(-4, 6), C(-5, -3) and D(4, -7). Write the quadrant of each point.

A(3, 2) = I Quadrant

B(-4, 6) = II Quadrant

C(-5, -3) = III Quadrant

D(4, -7) = IV Quadrant

Marking Scheme:
Each correct quadrant = 0.75 Mark
Total = 3 Marks

  1. Point P(7, -4) is reflected in:

(a) x-axis

(7, -4) → (7, 4)

(b) y-axis

(7, -4) → (-7, -4)

(c) origin

(7, -4) → (-7, 4)

Marking Scheme:
(a) 1 Mark
(b) 1 Mark
(c) 1 Mark
Total = 3 Marks

  1. Calculate the number of protons, electrons and neutrons in:

(a) 16O

Atomic Number = 8

Protons = 8
Electrons = 8
Neutrons = 16 − 8 = 8

(b) 23Na

Atomic Number = 11

Protons = 11
Electrons = 11
Neutrons = 23 − 11 = 12

Answer:

16O:
p = 8
e = 8
n = 8

23Na:
p = 11
e = 11
n = 12

Marking Scheme:
16O = 1.5 Marks
23Na = 1.5 Marks
Total = 3 Marks

  1. Calculate the average atomic mass of chlorine if it contains:
    75% 35Cl and 25% 37Cl.

Average Atomic Mass
= (75 × 35 + 25 × 37)/100
= (2625 + 925)/100
= 3550/100
= 35.5 u

Answer: 35.5 u

Marking Scheme:
Formula = 1 Mark
Substitution = 1 Mark
Answer = 1 Mark
Total = 3 Marks

  1. Calculate the number of protons, electrons and neutrons in 40Ca.

Atomic Number of Ca = 20

Protons = 20
Electrons = 20
Neutrons = 40 − 20 = 20

Answer:
Protons = 20
Electrons = 20
Neutrons = 20

Marking Scheme:
Protons = 1 Mark
Electrons = 1 Mark
Neutrons = 1 Mark
Total = 3 Marks

==================================================
SECTION D (4 MARKS EACH)
(Write Any 2) = 8 Marks

  1. Plot the points A(5, 4), B(-6, 3), C(-4, -5) and D(7, -2) and write:

(a) Quadrant of each point

A(5, 4) = I Quadrant

B(-6, 3) = II Quadrant

C(-4, -5) = III Quadrant

D(7, -2) = IV Quadrant

(b) Sign of x-coordinate and y-coordinate

A(5, 4) = (+ , +)

B(-6, 3) = (- , +)

C(-4, -5) = (- , -)

D(7, -2) = (+ , -)

Marking Scheme:
Quadrants = 2 Marks
Signs = 2 Marks
Total = 4 Marks

  1. An element has two isotopes:

70% isotope of mass 24 u
30% isotope of mass 26 u

Average Atomic Mass
= (70 × 24 + 30 × 26)/100
= (1680 + 780)/100
= 2460/100
= 24.6 u

Answer: 24.6 u

Marking Scheme:
Formula = 1 Mark
Substitution = 1 Mark
Calculation = 1 Mark
Answer = 1 Mark
Total = 4 Marks

  1. Complete the following:

Element: Carbon
Atomic Number = 6
Mass Number = 12

Protons = 6
Electrons = 6
Neutrons = 12 − 6 = 6

Element: Oxygen
Atomic Number = 8
Mass Number = 16

Protons = 8
Electrons = 8
Neutrons = 16 − 8 = 8

Element: Calcium
Atomic Number = 20
Mass Number = 40

Protons = 20
Electrons = 20
Neutrons = 40 − 20 = 20

Completed Table

Element Atomic No. Mass No. Protons Electrons Neutrons

Carbon 6 12 6 6 6

Oxygen 8 16 8 8 8

Calcium 20 40 20 20 20

Marking Scheme:
Carbon row = 1.33 Marks
Oxygen row = 1.33 Marks
Calcium row = 1.34 Marks

Total = 4 Marks

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GRAND TOTAL = 30 MARKS

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