Class 10 Science MCQ Worksheet Chapter 9 Light Reflection and Refraction | Detailed Solutions & Marking Scheme

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 VEDANT WORKSHEET SERIES - ACADEMIC YEAR 2026-27

Class: 10
Subject: Science
Chapter: Light – Reflection and Refraction
Time: 1 Hour
Maximum Marks: 30

SECTION A

MCQs (1 mark each)

Q1. A concave mirror forms an image of an object placed at infinity. The image will be:
A. At centre of curvature, real and inverted
B. At focus, real and inverted
C. At focus, virtual and erect
D. At pole, real and inverted

Q2. A convex mirror always forms an image which is:
A. Real and inverted
B. Virtual and erect
C. Real and erect
D. Virtual and inverted

Q3. The focal length of a concave mirror is 20 cm. The radius of curvature is:
A. 10 cm
B. 20 cm
C. 40 cm
D. 80 cm

Q4. A ray of light incident on a mirror retraces its path. The angle of incidence is:
A. 0°
B. 45°
C. 90°
D. Cannot be determined

Q5. Which of the following mirrors is used as a rear-view mirror in vehicles?
A. Plane mirror
B. Concave mirror
C. Convex mirror
D. Parabolic mirror

Q6. An object is placed between F and C of a concave mirror. The image formed is:
A. Virtual, erect, diminished
B. Real, inverted, enlarged
C. Real, erect, same size
D. Virtual, inverted, enlarged

Q7. The refractive index of a medium is defined as the ratio of:
A. Speed of light in medium to speed in vacuum
B. Speed of light in vacuum to speed in medium
C. Angle of incidence to angle of refraction
D. Frequency to wavelength

Q8. When light travels from air to glass, it bends:
A. Away from normal
B. Towards normal
C. Does not bend
D. Parallel to surface

Q9. A convex lens has focal length 15 cm. Its power is:
A. +6.67 D
B. -6.67 D
C. +0.067 D
D. -0.067 D

Q10. The image formed by a convex lens when object is at 2F is:
A. Virtual and erect
B. Real and same size
C. Real and enlarged
D. Virtual and diminished

Q11. The SI unit of power of a lens is:
A. Metre
B. Dioptre
C. Watt
D. Pascal

Q12. Which of the following has maximum refractive index?
A. Air
B. Water
C. Glass
D. Diamond

Q13. The magnification produced by a plane mirror is:
A. Greater than 1
B. Less than 1
C. Equal to 1
D. Zero

Q14. A lens that diverges light rays is called:
A. Convex lens
B. Concave lens
C. Plano-convex lens
D. Cylindrical lens

Q15. If the refractive index of a medium is 1.5, the speed of light in that medium is:
A. 3 × 10^8 m/s
B. 2 × 10^8 m/s
C. 1.5 × 10^8 m/s
D. 4.5 × 10^8 m/s

Assertion-Reason Questions (1 mark each)

For Q16–30, choose the correct option:
A. Both A and R are true, R is correct explanation of A
B. Both A and R are true, R is not correct explanation of A
C. A is true, R is false
D. A is false, R is true

Q16.
Assertion (A): A concave mirror can form both real and virtual images.
Reason (R): It depends on the position of the object with respect to focus.

Q17.
Assertion (A): A convex mirror is used as rear-view mirror.
Reason (R): It provides a wider field of view.

Q18.
Assertion (A): The refractive index of a medium depends on wavelength of light.
Reason (R): Different wavelengths travel at different speeds in a medium.

Q19.
Assertion (A): Light bends towards normal when it enters a denser medium.
Reason (R): Speed of light decreases in denser medium.

Q20.
Assertion (A): Power of a concave lens is negative.
Reason (R): Concave lens converges light rays.

Q21.
Assertion (A): Image formed by a plane mirror is laterally inverted.
Reason (R): The mirror reverses front and back.

Q22.
Assertion (A): A ray passing through the optical centre of a lens goes undeviated.
Reason (R): The surfaces of lens are parallel at optical centre.

Q23.
Assertion (A): Real images can be obtained on a screen.
Reason (R): Real images are formed by actual convergence of rays.

Q24.
Assertion (A): Convex lens is used to correct hypermetropia.
Reason (R): It converges incoming light rays.

Q25.
Assertion (A): When angle of incidence increases, angle of refraction also increases.
Reason (R): According to Snell’s law, ratio remains constant.

Q26.
Assertion (A): Magnification for virtual image is positive.
Reason (R): Virtual images are always erect.

Q27.
Assertion (A): A concave mirror cannot form virtual image.
Reason (R): It always forms real images.

Q28.
Assertion (A): Speed of light is maximum in vacuum.
Reason (R): Vacuum has zero refractive index.

Q29.
Assertion (A): A concave lens always forms diminished image.
Reason (R): It diverges light rays.

Q30.
Assertion (A): If focal length is small, power of lens is high.
Reason (R): Power is inversely proportional to focal length.

VEDANT WORKSHEET SERIES - ACADEMIC YEAR 2026-27
Class 10 | Science | Chapter: Light – Reflection and Refraction

DETAILED SOLVED ANSWER KEY WITH MARKING SCHEME

SECTION A – MCQs (1 mark each)

Q1. Correct Answer: B (1 mark)
Image of object at infinity in concave mirror is formed at focus, real and inverted.

Q2. Correct Answer: B (1 mark)
Convex mirror always forms virtual and erect image.

Q3. Correct Answer: C (1 mark)
R = 2f
R = 2 × 20 = 40 cm

Q4. Correct Answer: A (1 mark)
If ray retraces path → angle of incidence = 0°.

Q5. Correct Answer: C (1 mark)
Convex mirror gives wider field of view.

Q6. Correct Answer: B (1 mark)
Object between F and C → image beyond C, real, inverted, enlarged.

Q7. Correct Answer: B (1 mark)
Refractive index n = speed in vacuum / speed in medium

n = c / v

Q8. Correct Answer: B (1 mark)
Light bends towards normal in denser medium.

Q9. Correct Answer: A (1 mark)
Power P = 1/f (in metre)
f = 15 cm = 0.15 m

P = 1 / 0.15 = 6.67 D

Q10. Correct Answer: B (1 mark)
Object at 2F → image at 2F, real and same size.

Q11. Correct Answer: B (1 mark)
SI unit of power = dioptre.

Q12. Correct Answer: D (1 mark)
Diamond has highest refractive index.

Q13. Correct Answer: C (1 mark)
Plane mirror magnification m = +1.

Q14. Correct Answer: B (1 mark)
Concave lens diverges rays.

Q15. Correct Answer: B (1 mark)
n = c / v

v = c / n = (3 × 10^8) / 1.5
v = 2 × 10^8 m/s

SECTION A – Assertion Reason (1 mark each)

Q16. Correct Answer: A (1 mark)
A: True
R: True
Explanation: Nature depends on object position.

Q17. Correct Answer: A (1 mark)
A: True
R: True
Explanation: Wider field of view is reason.

Q18. Correct Answer: A (1 mark)
A: True
R: True
Explanation: Different wavelengths → different speeds → dispersion.

Q19. Correct Answer: A (1 mark)
A: True
R: True
Explanation: Speed decreases → bending towards normal.

Q20. Correct Answer: C (1 mark)
A: True
R: False
Concave lens diverges rays, not converges.

Q21. Correct Answer: C (1 mark)
A: True
R: False
Mirror reverses left-right, not front-back.

Q22. Correct Answer: A (1 mark)
A: True
R: True
Surfaces nearly parallel → no deviation.

Q23. Correct Answer: A (1 mark)
A: True
R: True
Real image forms by actual meeting of rays.

Q24. Correct Answer: A (1 mark)
A: True
R: True
Convex lens converges rays to correct vision.

Q25. Correct Answer: B (1 mark)
A: True
R: True
But R does not explain increase.

Q26. Correct Answer: A (1 mark)
A: True
R: True
Virtual images are erect → positive magnification.

Q27. Correct Answer: D (1 mark)
A: False
R: True
Concave mirror can form virtual image (object between P and F).

Q28. Correct Answer: C (1 mark)
A: True
R: False
Vacuum refractive index = 1, not zero.

Q29. Correct Answer: A (1 mark)
A: True
R: True
Diverging nature → always diminished.

Q30. Correct Answer: A (1 mark)
A: True
R: True
P = 1/f → smaller f → larger power.

FINAL MARKING SCHEME SUMMARY

MCQs: 15 × 1 = 15 marks
Assertion-Reason: 15 × 1 = 15 marks

Total = 30 marks


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