Class 12 Chemistry MCQ Test – Haloalkane and Haloarene (Chapter 6) | Full Chapter Test
Class 12 Chemistry – Chapter: Haloalkanes and Haloarenes (Short Notes)
These notes are designed for CBSE, GSEB, JEE and NEET students. It includes detailed theory, mechanisms, reactions, and exam-oriented explanations.
1. Introduction
Haloalkanes and haloarenes are organic compounds in which one or more hydrogen atoms of hydrocarbons are replaced by halogen atoms (F, Cl, Br, I).
- Haloalkanes (Alkyl halides): Halogen attached to sp³ hybridized carbon (R–X)
- Haloarenes (Aryl halides): Halogen attached to aromatic ring (Ar–X)
Example:
- CH₃Cl → Chloromethane (Haloalkane)
- C₆H₅Cl → Chlorobenzene (Haloarene)
2. Classification of Haloalkanes
Based on number of halogen atoms
- Mono halogen: CH₃Cl
- Di halogen: CH₂Cl₂
- Tri halogen: CHCl₃
- Tetra halogen: CCl₄
Based on carbon type
- Primary (1°): R–CH₂–X
- Secondary (2°): R₂CH–X
- Tertiary (3°): R₃C–X
3. Nomenclature (IUPAC System)
Rules for naming haloalkanes:
- Select longest carbon chain
- Number chain from nearest substituent
- Halogens are named as prefixes: fluoro, chloro, bromo, iodo
- Arrange alphabetically
Example: CH₃–CHCl–CH₃ → 2-chloropropane
4. Methods of Preparation
1. From Alcohols
ROH + HX → RX + H₂O
2. From Alkanes (Free radical halogenation)
CH₄ + Cl₂ → CH₃Cl + HCl (UV light)
3. From Alkenes
- Addition of HX → Haloalkane
- Addition of X₂ → Vicinal dihalides
5. Physical Properties
- Higher boiling point than hydrocarbons
- Boiling point increases with molecular mass
- Density increases with halogen atomic mass
- Soluble in organic solvents, insoluble in water
6. Chemical Reactions of Haloalkanes
1. Nucleophilic Substitution Reaction (SN1 & SN2)
SN1 Reaction:
- Two step reaction
- Carbocation intermediate formed
- Favoured by tertiary haloalkanes
SN2 Reaction:
- Single step reaction
- Backside attack
- Favoured by primary haloalkanes
2. Elimination Reaction
Formation of alkene by removal of HX (dehydrohalogenation)
CH₃–CH₂Br + alc. KOH → CH₂=CH₂ + KBr + H₂O
3. Reaction with Metals
- Wurtz Reaction: 2R–X + 2Na → R–R
- Grignard Reagent: R–X + Mg → R–MgX
7. Haloarenes (Aryl Halides)
Why less reactive?
- Resonance stabilisation of C–X bond
- Partial double bond character
- sp² carbon stronger bond
8. Chemical Reactions of Haloarenes
1. Electrophilic Substitution Reactions
- Nitration
- Halogenation
- Sulphonation
Halogen is ortho/para directing but deactivating.
2. Nucleophilic Substitution
Chlorobenzene reacts only under drastic conditions due to resonance stability.
C₆H₅Cl + NaOH (300°C, 200 atm) → C₆H₅OH
9. Polyhalogen Compounds
- CHCl₃ → Chloroform (anaesthetic use)
- CCl₄ → Carbon tetrachloride (solvent, toxic)
- Dichloromethane → Paint remover
10. Applications
- Used in pharmaceuticals
- Used as solvents
- Used in refrigerants
- Used in synthesis of polymers
11. Key Summary Formulas
\( SN1 \rightarrow \text{Two-step reaction via carbocation} \)
\( SN2 \rightarrow \text{One-step backside attack} \)
\( R–X + Mg \rightarrow R–MgX \)
⬇️ Revise carefully and practice numericals + mechanisms for exams
Class 12 Chemistry
Chapter : Haloalkanes and Haloarenes | Full MCQ Test
Class 12 Chemistry Chapter: Haloalkanes and Haloarenes
This chapter is a core part of Organic Chemistry in Class 12. It explains the substitution reactions, preparation methods, and behavior of halo compounds. It is extremely important for CBSE board exams, NEET, and JEE due to mechanism-based questions and conversions.
Learning Outcomes
After completing this chapter, students will be able to:
- Understand the classification of haloalkanes and haloarenes.
- Differentiate between primary, secondary, and tertiary haloalkanes.
- Explain IUPAC naming of halo compounds.
- Understand nucleophilic substitution reactions (SN1 and SN2 mechanisms).
- Explain elimination reactions leading to alkene formation.
- Understand the preparation of haloalkanes from alcohols and alkanes.
- Explain the reactivity difference between haloalkanes and haloarenes.
- Understand resonance effect in haloarenes.
- Learn important reactions like Wurtz reaction and Grignard reagent formation.
Real Life Applications
Haloalkanes and haloarenes are widely used in daily life and industry:
- Medicines: Many drugs and anesthetics contain halogen compounds.
- Solvents: Carbon tetrachloride and dichloromethane are used as industrial solvents.
- Refrigerants: Freons (CFCs) were used in refrigerators and ACs.
- Fire Extinguishers: Halogen compounds like CCl₄ were earlier used.
- Pesticides: DDT is a halogen-containing compound used in agriculture.
- Organic Synthesis: Grignard reagents are used to form carbon-carbon bonds.
Common Mistakes Students Make
- Confusing SN1 and SN2 mechanisms.
- Not understanding carbocation stability order.
- Incorrect identification of primary, secondary, tertiary haloalkanes.
- Ignoring resonance in haloarenes leading to wrong reactivity answers.
- Confusion between elimination and substitution reactions.
- Wrong application of IUPAC naming rules.
Conclusion
The chapter “Haloalkanes and Haloarenes” is highly important for organic chemistry understanding. Focus on reaction mechanisms, especially SN1, SN2, and elimination reactions. Regular practice of conversions and mechanisms will help you score high in exams.
Class 12 Chemistry: Haloalkanes and Haloarenes
10 Detailed Solved Examples
Classify CH3–CH2–CH2Cl.
Solution:
Carbon attached to Cl is primary carbon (1°).
So compound is 1° haloalkane.
Predict mechanism for (CH3)3C–Cl.
Solution:
Tertiary haloalkane forms stable carbocation.
So reaction follows SN1 mechanism.
Which reacts faster in SN2: CH3Cl or (CH3)3CCl?
Solution:
Less steric hindrance → faster SN2.
So CH3Cl reacts faster.
CH3Br + Na (dry ether) → ?
Solution:
2CH3Br + 2Na → C2H6 + 2NaBr
Product: Ethane
CH3Cl + Mg (dry ether) → ?
Solution:
CH3MgCl formed → Grignard reagent
Why is chlorobenzene less reactive?
Solution:
Due to resonance → partial double bond character → strong C–Cl bond.
C6H5Cl + NaOH → conditions?
Solution:
Requires high temperature and pressure (Dow process).
Which is best leaving group: F⁻, Cl⁻, Br⁻, I⁻?
Solution:
I⁻ is largest and most stable → best leaving group.
Name CH3–CHCl–CH3
Solution:
Parent chain propane + Cl at position 2 → 2-chloropropane.
CH3–CH2Br + alcoholic KOH → product?
Solution:
Elimination occurs → CH2=CH2 (ethene)
10 Important FAQs
Organic compounds in which halogen replaces hydrogen in alkanes.
Due to resonance stabilization of C–X bond in benzene ring.
SN1: two-step, carbocation; SN2: one-step, backside attack.
Organomagnesium compound (RMgX) used in carbon-carbon bond formation.
Due to steric hindrance.
Coupling of alkyl halides using sodium in dry ether.
Due to strong C–F bond strength.
Removal of HX to form alkene.
They cannot form hydrogen bonds with water.
Used in medicines, synthesis, solvents, and industrial chemicals.
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